3[d-8]-5=9[d+2]+1

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Solution for 3[d-8]-5=9[d+2]+1 equation:


Simplifying
3[d + -8] + -5 = 9[d + 2] + 1

Reorder the terms:
3[-8 + d] + -5 = 9[d + 2] + 1
[-8 * 3 + d * 3] + -5 = 9[d + 2] + 1
[-24 + 3d] + -5 = 9[d + 2] + 1

Reorder the terms:
-24 + -5 + 3d = 9[d + 2] + 1

Combine like terms: -24 + -5 = -29
-29 + 3d = 9[d + 2] + 1

Reorder the terms:
-29 + 3d = 9[2 + d] + 1
-29 + 3d = [2 * 9 + d * 9] + 1
-29 + 3d = [18 + 9d] + 1

Reorder the terms:
-29 + 3d = 18 + 1 + 9d

Combine like terms: 18 + 1 = 19
-29 + 3d = 19 + 9d

Solving
-29 + 3d = 19 + 9d

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '-9d' to each side of the equation.
-29 + 3d + -9d = 19 + 9d + -9d

Combine like terms: 3d + -9d = -6d
-29 + -6d = 19 + 9d + -9d

Combine like terms: 9d + -9d = 0
-29 + -6d = 19 + 0
-29 + -6d = 19

Add '29' to each side of the equation.
-29 + 29 + -6d = 19 + 29

Combine like terms: -29 + 29 = 0
0 + -6d = 19 + 29
-6d = 19 + 29

Combine like terms: 19 + 29 = 48
-6d = 48

Divide each side by '-6'.
d = -8

Simplifying
d = -8

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